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Java example source code file (IntMath.java)

This example Java source code file (IntMath.java) is included in the alvinalexander.com "Java Source Code Warehouse" project. The intent of this project is to help you "Learn Java by Example" TM.

Learn more about this Java project at its project page.

Java - Java tags/keywords

assertionerror, beta, bigintegermath, ceiling, floor_sqrt_max_int, gwtincompatible, half_down, half_even, half_up, math, roundingmode, suppresswarnings, unnecessary, visiblefortesting

The IntMath.java Java example source code

/*
 * Copyright (C) 2011 The Guava Authors
 *
 * Licensed under the Apache License, Version 2.0 (the "License"); you may not use this file except
 * in compliance with the License. You may obtain a copy of the License at
 *
 * http://www.apache.org/licenses/LICENSE-2.0
 *
 * Unless required by applicable law or agreed to in writing, software distributed under the License
 * is distributed on an "AS IS" BASIS, WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND, either express
 * or implied. See the License for the specific language governing permissions and limitations under
 * the License.
 */

package com.google.common.math;

import static com.google.common.base.Preconditions.checkArgument;
import static com.google.common.base.Preconditions.checkNotNull;
import static com.google.common.math.MathPreconditions.checkNoOverflow;
import static com.google.common.math.MathPreconditions.checkNonNegative;
import static com.google.common.math.MathPreconditions.checkPositive;
import static com.google.common.math.MathPreconditions.checkRoundingUnnecessary;
import static java.lang.Math.abs;
import static java.lang.Math.min;
import static java.math.RoundingMode.HALF_EVEN;
import static java.math.RoundingMode.HALF_UP;

import com.google.common.annotations.Beta;
import com.google.common.annotations.GwtCompatible;
import com.google.common.annotations.GwtIncompatible;
import com.google.common.annotations.VisibleForTesting;
import com.google.common.primitives.Ints;

import java.math.BigInteger;
import java.math.RoundingMode;

/**
 * A class for arithmetic on values of type {@code int}. Where possible, methods are defined and
 * named analogously to their {@code BigInteger} counterparts.
 *
 * <p>The implementations of many methods in this class are based on material from Henry S. Warren,
 * Jr.'s <i>Hacker's Delight, (Addison Wesley, 2002).
 *
 * <p>Similar functionality for {@code long} and for {@link BigInteger} can be found in
 * {@link LongMath} and {@link BigIntegerMath} respectively. For other common operations on
 * {@code int} values, see {@link com.google.common.primitives.Ints}.
 *
 * @author Louis Wasserman
 * @since 11.0
 */
@GwtCompatible(emulated = true)
public final class IntMath {
  // NOTE: Whenever both tests are cheap and functional, it's faster to use &, | instead of &&, ||

  @VisibleForTesting static final int MAX_SIGNED_POWER_OF_TWO = 1 << (Integer.SIZE - 2);

  /**
   * Returns the smallest power of two greater than or equal to {@code x}.  This is equivalent to
   * {@code checkedPow(2, log2(x, CEILING))}.
   *
   * @throws IllegalArgumentException if {@code x <= 0}
   * @throws ArithmeticException of the next-higher power of two is not representable as an
   *         {@code int}, i.e. when {@code x > 2^30}
   * @since 20.0
   */
  @Beta
  public static int ceilingPowerOfTwo(int x) {
    checkPositive("x", x);
    if (x > MAX_SIGNED_POWER_OF_TWO) {
      throw new ArithmeticException("ceilingPowerOfTwo(" + x + ") not representable as an int");
    }
    return 1 << -Integer.numberOfLeadingZeros(x - 1);
  }

  /**
   * Returns the largest power of two less than or equal to {@code x}.  This is equivalent to
   * {@code checkedPow(2, log2(x, FLOOR))}.
   *
   * @throws IllegalArgumentException if {@code x <= 0}
   * @since 20.0
   */
  @Beta
  public static int floorPowerOfTwo(int x) {
    checkPositive("x", x);
    return Integer.highestOneBit(x);
  }

  /**
   * Returns {@code true} if {@code x} represents a power of two.
   *
   * <p>This differs from {@code Integer.bitCount(x) == 1}, because
   * {@code Integer.bitCount(Integer.MIN_VALUE) == 1}, but {@link Integer#MIN_VALUE} is not a power
   * of two.
   */
  public static boolean isPowerOfTwo(int x) {
    return x > 0 & (x & (x - 1)) == 0;
  }

  /**
   * Returns 1 if {@code x < y} as unsigned integers, and 0 otherwise. Assumes that x - y fits into
   * a signed int. The implementation is branch-free, and benchmarks suggest it is measurably (if
   * narrowly) faster than the straightforward ternary expression.
   */
  @VisibleForTesting
  static int lessThanBranchFree(int x, int y) {
    // The double negation is optimized away by normal Java, but is necessary for GWT
    // to make sure bit twiddling works as expected.
    return ~~(x - y) >>> (Integer.SIZE - 1);
  }

  /**
   * Returns the base-2 logarithm of {@code x}, rounded according to the specified rounding mode.
   *
   * @throws IllegalArgumentException if {@code x <= 0}
   * @throws ArithmeticException if {@code mode} is {@link RoundingMode#UNNECESSARY} and {@code x}
   *     is not a power of two
   */
  @SuppressWarnings("fallthrough")
  // TODO(kevinb): remove after this warning is disabled globally
  public static int log2(int x, RoundingMode mode) {
    checkPositive("x", x);
    switch (mode) {
      case UNNECESSARY:
        checkRoundingUnnecessary(isPowerOfTwo(x));
        // fall through
      case DOWN:
      case FLOOR:
        return (Integer.SIZE - 1) - Integer.numberOfLeadingZeros(x);

      case UP:
      case CEILING:
        return Integer.SIZE - Integer.numberOfLeadingZeros(x - 1);

      case HALF_DOWN:
      case HALF_UP:
      case HALF_EVEN:
        // Since sqrt(2) is irrational, log2(x) - logFloor cannot be exactly 0.5
        int leadingZeros = Integer.numberOfLeadingZeros(x);
        int cmp = MAX_POWER_OF_SQRT2_UNSIGNED >>> leadingZeros;
        // floor(2^(logFloor + 0.5))
        int logFloor = (Integer.SIZE - 1) - leadingZeros;
        return logFloor + lessThanBranchFree(cmp, x);

      default:
        throw new AssertionError();
    }
  }

  /** The biggest half power of two that can fit in an unsigned int. */
  @VisibleForTesting static final int MAX_POWER_OF_SQRT2_UNSIGNED = 0xB504F333;

  /**
   * Returns the base-10 logarithm of {@code x}, rounded according to the specified rounding mode.
   *
   * @throws IllegalArgumentException if {@code x <= 0}
   * @throws ArithmeticException if {@code mode} is {@link RoundingMode#UNNECESSARY} and {@code x}
   *     is not a power of ten
   */
  @GwtIncompatible // need BigIntegerMath to adequately test
  @SuppressWarnings("fallthrough")
  public static int log10(int x, RoundingMode mode) {
    checkPositive("x", x);
    int logFloor = log10Floor(x);
    int floorPow = powersOf10[logFloor];
    switch (mode) {
      case UNNECESSARY:
        checkRoundingUnnecessary(x == floorPow);
        // fall through
      case FLOOR:
      case DOWN:
        return logFloor;
      case CEILING:
      case UP:
        return logFloor + lessThanBranchFree(floorPow, x);
      case HALF_DOWN:
      case HALF_UP:
      case HALF_EVEN:
        // sqrt(10) is irrational, so log10(x) - logFloor is never exactly 0.5
        return logFloor + lessThanBranchFree(halfPowersOf10[logFloor], x);
      default:
        throw new AssertionError();
    }
  }

  private static int log10Floor(int x) {
    /*
     * Based on Hacker's Delight Fig. 11-5, the two-table-lookup, branch-free implementation.
     *
     * The key idea is that based on the number of leading zeros (equivalently, floor(log2(x))), we
     * can narrow the possible floor(log10(x)) values to two. For example, if floor(log2(x)) is 6,
     * then 64 <= x < 128, so floor(log10(x)) is either 1 or 2.
     */
    int y = maxLog10ForLeadingZeros[Integer.numberOfLeadingZeros(x)];
    /*
     * y is the higher of the two possible values of floor(log10(x)). If x < 10^y, then we want the
     * lower of the two possible values, or y - 1, otherwise, we want y.
     */
    return y - lessThanBranchFree(x, powersOf10[y]);
  }

  // maxLog10ForLeadingZeros[i] == floor(log10(2^(Long.SIZE - i)))
  @VisibleForTesting
  static final byte[] maxLog10ForLeadingZeros = {
    9, 9, 9, 8, 8, 8, 7, 7, 7, 6, 6, 6, 6, 5, 5, 5, 4, 4, 4, 3, 3, 3, 3, 2, 2, 2, 1, 1, 1, 0, 0, 0,
    0
  };

  @VisibleForTesting
  static final int[] powersOf10 = {
    1, 10, 100, 1000, 10000, 100000, 1000000, 10000000, 100000000, 1000000000
  };

  // halfPowersOf10[i] = largest int less than 10^(i + 0.5)
  @VisibleForTesting
  static final int[] halfPowersOf10 = {
    3, 31, 316, 3162, 31622, 316227, 3162277, 31622776, 316227766, Integer.MAX_VALUE
  };

  /**
   * Returns {@code b} to the {@code k}th power. Even if the result overflows, it will be equal to
   * {@code BigInteger.valueOf(b).pow(k).intValue()}. This implementation runs in {@code O(log k)}
   * time.
   *
   * <p>Compare {@link #checkedPow}, which throws an {@link ArithmeticException} upon overflow.
   *
   * @throws IllegalArgumentException if {@code k < 0}
   */
  @GwtIncompatible // failing tests
  public static int pow(int b, int k) {
    checkNonNegative("exponent", k);
    switch (b) {
      case 0:
        return (k == 0) ? 1 : 0;
      case 1:
        return 1;
      case (-1):
        return ((k & 1) == 0) ? 1 : -1;
      case 2:
        return (k < Integer.SIZE) ? (1 << k) : 0;
      case (-2):
        if (k < Integer.SIZE) {
          return ((k & 1) == 0) ? (1 << k) : -(1 << k);
        } else {
          return 0;
        }
      default:
        // continue below to handle the general case
    }
    for (int accum = 1; ; k >>= 1) {
      switch (k) {
        case 0:
          return accum;
        case 1:
          return b * accum;
        default:
          accum *= ((k & 1) == 0) ? 1 : b;
          b *= b;
      }
    }
  }

  /**
   * Returns the square root of {@code x}, rounded with the specified rounding mode.
   *
   * @throws IllegalArgumentException if {@code x < 0}
   * @throws ArithmeticException if {@code mode} is {@link RoundingMode#UNNECESSARY} and
   *     {@code sqrt(x)} is not an integer
   */
  @GwtIncompatible // need BigIntegerMath to adequately test
  @SuppressWarnings("fallthrough")
  public static int sqrt(int x, RoundingMode mode) {
    checkNonNegative("x", x);
    int sqrtFloor = sqrtFloor(x);
    switch (mode) {
      case UNNECESSARY:
        checkRoundingUnnecessary(sqrtFloor * sqrtFloor == x); // fall through
      case FLOOR:
      case DOWN:
        return sqrtFloor;
      case CEILING:
      case UP:
        return sqrtFloor + lessThanBranchFree(sqrtFloor * sqrtFloor, x);
      case HALF_DOWN:
      case HALF_UP:
      case HALF_EVEN:
        int halfSquare = sqrtFloor * sqrtFloor + sqrtFloor;
        /*
         * We wish to test whether or not x <= (sqrtFloor + 0.5)^2 = halfSquare + 0.25. Since both x
         * and halfSquare are integers, this is equivalent to testing whether or not x <=
         * halfSquare. (We have to deal with overflow, though.)
         *
         * If we treat halfSquare as an unsigned int, we know that
         *            sqrtFloor^2 <= x < (sqrtFloor + 1)^2
         * halfSquare - sqrtFloor <= x < halfSquare + sqrtFloor + 1
         * so |x - halfSquare| <= sqrtFloor.  Therefore, it's safe to treat x - halfSquare as a
         * signed int, so lessThanBranchFree is safe for use.
         */
        return sqrtFloor + lessThanBranchFree(halfSquare, x);
      default:
        throw new AssertionError();
    }
  }

  private static int sqrtFloor(int x) {
    // There is no loss of precision in converting an int to a double, according to
    // http://java.sun.com/docs/books/jls/third_edition/html/conversions.html#5.1.2
    return (int) Math.sqrt(x);
  }

  /**
   * Returns the result of dividing {@code p} by {@code q}, rounding using the specified
   * {@code RoundingMode}.
   *
   * @throws ArithmeticException if {@code q == 0}, or if {@code mode == UNNECESSARY} and {@code a}
   *     is not an integer multiple of {@code b}
   */
  @SuppressWarnings("fallthrough")
  public static int divide(int p, int q, RoundingMode mode) {
    checkNotNull(mode);
    if (q == 0) {
      throw new ArithmeticException("/ by zero"); // for GWT
    }
    int div = p / q;
    int rem = p - q * div; // equal to p % q

    if (rem == 0) {
      return div;
    }

    /*
     * Normal Java division rounds towards 0, consistently with RoundingMode.DOWN. We just have to
     * deal with the cases where rounding towards 0 is wrong, which typically depends on the sign of
     * p / q.
     *
     * signum is 1 if p and q are both nonnegative or both negative, and -1 otherwise.
     */
    int signum = 1 | ((p ^ q) >> (Integer.SIZE - 1));
    boolean increment;
    switch (mode) {
      case UNNECESSARY:
        checkRoundingUnnecessary(rem == 0);
        // fall through
      case DOWN:
        increment = false;
        break;
      case UP:
        increment = true;
        break;
      case CEILING:
        increment = signum > 0;
        break;
      case FLOOR:
        increment = signum < 0;
        break;
      case HALF_EVEN:
      case HALF_DOWN:
      case HALF_UP:
        int absRem = abs(rem);
        int cmpRemToHalfDivisor = absRem - (abs(q) - absRem);
        // subtracting two nonnegative ints can't overflow
        // cmpRemToHalfDivisor has the same sign as compare(abs(rem), abs(q) / 2).
        if (cmpRemToHalfDivisor == 0) { // exactly on the half mark
          increment = (mode == HALF_UP || (mode == HALF_EVEN & (div & 1) != 0));
        } else {
          increment = cmpRemToHalfDivisor > 0; // closer to the UP value
        }
        break;
      default:
        throw new AssertionError();
    }
    return increment ? div + signum : div;
  }

  /**
   * Returns {@code x mod m}, a non-negative value less than {@code m}. This differs from
   * {@code x % m}, which might be negative.
   *
   * <p>For example:
 {@code
   *
   * mod(7, 4) == 3
   * mod(-7, 4) == 1
   * mod(-1, 4) == 3
   * mod(-8, 4) == 0
   * mod(8, 4) == 0}</pre>
   *
   * @throws ArithmeticException if {@code m <= 0}
   * @see <a href="http://docs.oracle.com/javase/specs/jls/se7/html/jls-15.html#jls-15.17.3">
   *     Remainder Operator</a>
   */
  public static int mod(int x, int m) {
    if (m <= 0) {
      throw new ArithmeticException("Modulus " + m + " must be > 0");
    }
    int result = x % m;
    return (result >= 0) ? result : result + m;
  }

  /**
   * Returns the greatest common divisor of {@code a, b}. Returns {@code 0} if
   * {@code a == 0 && b == 0}.
   *
   * @throws IllegalArgumentException if {@code a < 0} or {@code b < 0}
   */
  public static int gcd(int a, int b) {
    /*
     * The reason we require both arguments to be >= 0 is because otherwise, what do you return on
     * gcd(0, Integer.MIN_VALUE)? BigInteger.gcd would return positive 2^31, but positive 2^31 isn't
     * an int.
     */
    checkNonNegative("a", a);
    checkNonNegative("b", b);
    if (a == 0) {
      // 0 % b == 0, so b divides a, but the converse doesn't hold.
      // BigInteger.gcd is consistent with this decision.
      return b;
    } else if (b == 0) {
      return a; // similar logic
    }
    /*
     * Uses the binary GCD algorithm; see http://en.wikipedia.org/wiki/Binary_GCD_algorithm. This is
     * >40% faster than the Euclidean algorithm in benchmarks.
     */
    int aTwos = Integer.numberOfTrailingZeros(a);
    a >>= aTwos; // divide out all 2s
    int bTwos = Integer.numberOfTrailingZeros(b);
    b >>= bTwos; // divide out all 2s
    while (a != b) { // both a, b are odd
      // The key to the binary GCD algorithm is as follows:
      // Both a and b are odd. Assume a > b; then gcd(a - b, b) = gcd(a, b).
      // But in gcd(a - b, b), a - b is even and b is odd, so we can divide out powers of two.

      // We bend over backwards to avoid branching, adapting a technique from
      // http://graphics.stanford.edu/~seander/bithacks.html#IntegerMinOrMax

      int delta = a - b; // can't overflow, since a and b are nonnegative

      int minDeltaOrZero = delta & (delta >> (Integer.SIZE - 1));
      // equivalent to Math.min(delta, 0)

      a = delta - minDeltaOrZero - minDeltaOrZero; // sets a to Math.abs(a - b)
      // a is now nonnegative and even

      b += minDeltaOrZero; // sets b to min(old a, b)
      a >>= Integer.numberOfTrailingZeros(a); // divide out all 2s, since 2 doesn't divide b
    }
    return a << min(aTwos, bTwos);
  }

  /**
   * Returns the sum of {@code a} and {@code b}, provided it does not overflow.
   *
   * @throws ArithmeticException if {@code a + b} overflows in signed {@code int} arithmetic
   */
  public static int checkedAdd(int a, int b) {
    long result = (long) a + b;
    checkNoOverflow(result == (int) result);
    return (int) result;
  }

  /**
   * Returns the difference of {@code a} and {@code b}, provided it does not overflow.
   *
   * @throws ArithmeticException if {@code a - b} overflows in signed {@code int} arithmetic
   */
  public static int checkedSubtract(int a, int b) {
    long result = (long) a - b;
    checkNoOverflow(result == (int) result);
    return (int) result;
  }

  /**
   * Returns the product of {@code a} and {@code b}, provided it does not overflow.
   *
   * @throws ArithmeticException if {@code a * b} overflows in signed {@code int} arithmetic
   */
  public static int checkedMultiply(int a, int b) {
    long result = (long) a * b;
    checkNoOverflow(result == (int) result);
    return (int) result;
  }

  /**
   * Returns the {@code b} to the {@code k}th power, provided it does not overflow.
   *
   * <p>{@link #pow} may be faster, but does not check for overflow.
   *
   * @throws ArithmeticException if {@code b} to the {@code k}th power overflows in signed
   *     {@code int} arithmetic
   */
  public static int checkedPow(int b, int k) {
    checkNonNegative("exponent", k);
    switch (b) {
      case 0:
        return (k == 0) ? 1 : 0;
      case 1:
        return 1;
      case (-1):
        return ((k & 1) == 0) ? 1 : -1;
      case 2:
        checkNoOverflow(k < Integer.SIZE - 1);
        return 1 << k;
      case (-2):
        checkNoOverflow(k < Integer.SIZE);
        return ((k & 1) == 0) ? 1 << k : -1 << k;
      default:
        // continue below to handle the general case
    }
    int accum = 1;
    while (true) {
      switch (k) {
        case 0:
          return accum;
        case 1:
          return checkedMultiply(accum, b);
        default:
          if ((k & 1) != 0) {
            accum = checkedMultiply(accum, b);
          }
          k >>= 1;
          if (k > 0) {
            checkNoOverflow(-FLOOR_SQRT_MAX_INT <= b & b <= FLOOR_SQRT_MAX_INT);
            b *= b;
          }
      }
    }
  }

  /**
   * Returns the sum of {@code a} and {@code b} unless it would overflow or underflow in which case
   * {@code Integer.MAX_VALUE} or {@code Integer.MIN_VALUE} is returned, respectively.
   *
   * @since 20.0
   */
  @Beta
  public static int saturatedAdd(int a, int b) {
    return Ints.saturatedCast((long) a + b);
  }

  /**
   * Returns the difference of {@code a} and {@code b} unless it would overflow or underflow in
   * which case {@code Integer.MAX_VALUE} or {@code Integer.MIN_VALUE} is returned, respectively.
   *
   * @since 20.0
   */
  @Beta
  public static int saturatedSubtract(int a, int b) {
    return Ints.saturatedCast((long) a - b);
  }

  /**
   * Returns the product of {@code a} and {@code b} unless it would overflow or underflow in which
   * case {@code Integer.MAX_VALUE} or {@code Integer.MIN_VALUE} is returned, respectively.
   *
   * @since 20.0
   */
  @Beta
  public static int saturatedMultiply(int a, int b) {
    return Ints.saturatedCast((long) a * b);
  }

  /**
   * Returns the {@code b} to the {@code k}th power, unless it would overflow or underflow in which
   * case {@code Integer.MAX_VALUE} or {@code Integer.MIN_VALUE} is returned, respectively.
   *
   * @since 20.0
   */
  @Beta
  public static int saturatedPow(int b, int k) {
    checkNonNegative("exponent", k);
    switch (b) {
      case 0:
        return (k == 0) ? 1 : 0;
      case 1:
        return 1;
      case (-1):
        return ((k & 1) == 0) ? 1 : -1;
      case 2:
        if (k >= Integer.SIZE - 1) {
          return Integer.MAX_VALUE;
        }
        return 1 << k;
      case (-2):
        if (k >= Integer.SIZE) {
          return Integer.MAX_VALUE + (k & 1);
        }
        return ((k & 1) == 0) ? 1 << k : -1 << k;
      default:
        // continue below to handle the general case
    }
    int accum = 1;
    // if b is negative and k is odd then the limit is MIN otherwise the limit is MAX
    int limit = Integer.MAX_VALUE + ((b >>> Integer.SIZE - 1) & (k & 1));
    while (true) {
      switch (k) {
        case 0:
          return accum;
        case 1:
          return saturatedMultiply(accum, b);
        default:
          if ((k & 1) != 0) {
            accum = saturatedMultiply(accum, b);
          }
          k >>= 1;
          if (k > 0) {
            if (-FLOOR_SQRT_MAX_INT > b | b > FLOOR_SQRT_MAX_INT) {
              return limit;
            }
            b *= b;
          }
      }
    }
  }

  @VisibleForTesting static final int FLOOR_SQRT_MAX_INT = 46340;

  /**
   * Returns {@code n!}, that is, the product of the first {@code n} positive integers, {@code 1} if
   * {@code n == 0}, or {@link Integer#MAX_VALUE} if the result does not fit in a {@code int}.
   *
   * @throws IllegalArgumentException if {@code n < 0}
   */
  public static int factorial(int n) {
    checkNonNegative("n", n);
    return (n < factorials.length) ? factorials[n] : Integer.MAX_VALUE;
  }

  private static final int[] factorials = {
    1,
    1,
    1 * 2,
    1 * 2 * 3,
    1 * 2 * 3 * 4,
    1 * 2 * 3 * 4 * 5,
    1 * 2 * 3 * 4 * 5 * 6,
    1 * 2 * 3 * 4 * 5 * 6 * 7,
    1 * 2 * 3 * 4 * 5 * 6 * 7 * 8,
    1 * 2 * 3 * 4 * 5 * 6 * 7 * 8 * 9,
    1 * 2 * 3 * 4 * 5 * 6 * 7 * 8 * 9 * 10,
    1 * 2 * 3 * 4 * 5 * 6 * 7 * 8 * 9 * 10 * 11,
    1 * 2 * 3 * 4 * 5 * 6 * 7 * 8 * 9 * 10 * 11 * 12
  };

  /**
   * Returns {@code n} choose {@code k}, also known as the binomial coefficient of {@code n} and
   * {@code k}, or {@link Integer#MAX_VALUE} if the result does not fit in an {@code int}.
   *
   * @throws IllegalArgumentException if {@code n < 0}, {@code k < 0} or {@code k > n}
   */
  @GwtIncompatible // need BigIntegerMath to adequately test
  public static int binomial(int n, int k) {
    checkNonNegative("n", n);
    checkNonNegative("k", k);
    checkArgument(k <= n, "k (%s) > n (%s)", k, n);
    if (k > (n >> 1)) {
      k = n - k;
    }
    if (k >= biggestBinomials.length || n > biggestBinomials[k]) {
      return Integer.MAX_VALUE;
    }
    switch (k) {
      case 0:
        return 1;
      case 1:
        return n;
      default:
        long result = 1;
        for (int i = 0; i < k; i++) {
          result *= n - i;
          result /= i + 1;
        }
        return (int) result;
    }
  }

  // binomial(biggestBinomials[k], k) fits in an int, but not binomial(biggestBinomials[k]+1,k).
  @VisibleForTesting
  static int[] biggestBinomials = {
    Integer.MAX_VALUE,
    Integer.MAX_VALUE,
    65536,
    2345,
    477,
    193,
    110,
    75,
    58,
    49,
    43,
    39,
    37,
    35,
    34,
    34,
    33
  };

  /**
   * Returns the arithmetic mean of {@code x} and {@code y}, rounded towards negative infinity. This
   * method is overflow resilient.
   *
   * @since 14.0
   */
  public static int mean(int x, int y) {
    // Efficient method for computing the arithmetic mean.
    // The alternative (x + y) / 2 fails for large values.
    // The alternative (x + y) >>> 1 fails for negative values.
    return (x & y) + ((x ^ y) >> 1);
  }

  /**
   * Returns {@code true} if {@code n} is a
   * <a href="http://mathworld.wolfram.com/PrimeNumber.html">prime number: an integer greater
   * than one</i> that cannot be factored into a product of smaller positive integers.
   * Returns {@code false} if {@code n} is zero, one, or a composite number (one which <i>can
   * be factored into smaller positive integers).
   *
   * <p>To test larger numbers, use {@link LongMath#isPrime} or {@link BigInteger#isProbablePrime}.
   *
   * @throws IllegalArgumentException if {@code n} is negative
   * @since 20.0
   */
  @GwtIncompatible // TODO
  @Beta
  public static boolean isPrime(int n) {
    return LongMath.isPrime(n);
  }

  private IntMath() {}
}

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