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The source codepackage org.apache.lucene.analysis.de; /** * Copyright 2004 The Apache Software Foundation * * Licensed under the Apache License, Version 2.0 (the "License"); * you may not use this file except in compliance with the License. * You may obtain a copy of the License at * * http://www.apache.org/licenses/LICENSE-2.0 * * Unless required by applicable law or agreed to in writing, software * distributed under the License is distributed on an "AS IS" BASIS, * WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied. * See the License for the specific language governing permissions and * limitations under the License. */ /** * A stemmer for German words. The algorithm is based on the report * "A Fast and Simple Stemming Algorithm for German Words" by Jörg * Caumanns (joerg.caumanns@isst.fhg.de). * * @author Gerhard Schwarz * @version $Id: GermanStemmer.java,v 1.11 2004/05/30 20:24:20 otis Exp $ */ public class GermanStemmer { /** * Buffer for the terms while stemming them. */ private StringBuffer sb = new StringBuffer(); /** * Amount of characters that are removed with substitute() while stemming. */ private int substCount = 0; /** * Stemms the given term to an unique discriminator. * * @param term The term that should be stemmed. * @return Discriminator for term */ protected String stem( String term ) { // Use lowercase for medium stemming. term = term.toLowerCase(); if ( !isStemmable( term ) ) return term; // Reset the StringBuffer. sb.delete( 0, sb.length() ); sb.insert( 0, term ); // Stemming starts here... substitute( sb ); strip( sb ); optimize( sb ); resubstitute( sb ); removeParticleDenotion( sb ); return sb.toString(); } /** * Checks if a term could be stemmed. * * @return true if, and only if, the given term consists in letters. */ private boolean isStemmable( String term ) { for ( int c = 0; c < term.length(); c++ ) { if ( !Character.isLetter( term.charAt( c ) ) ) return false; } return true; } /** * suffix stripping (stemming) on the current term. The stripping is reduced * to the seven "base" suffixes "e", "s", "n", "t", "em", "er" and * "nd", * from which all regular suffixes are build of. The simplification causes * some overstemming, and way more irregular stems, but still provides unique. * discriminators in the most of those cases. * The algorithm is context free, except of the length restrictions. */ private void strip( StringBuffer buffer ) { boolean doMore = true; while ( doMore && buffer.length() > 3 ) { if ( ( buffer.length() + substCount > 5 ) && buffer.substring( buffer.length() - 2, buffer.length() ).equals( "nd" ) ) { buffer.delete( buffer.length() - 2, buffer.length() ); } else if ( ( buffer.length() + substCount > 4 ) && buffer.substring( buffer.length() - 2, buffer.length() ).equals( "em" ) ) { buffer.delete( buffer.length() - 2, buffer.length() ); } else if ( ( buffer.length() + substCount > 4 ) && buffer.substring( buffer.length() - 2, buffer.length() ).equals( "er" ) ) { buffer.delete( buffer.length() - 2, buffer.length() ); } else if ( buffer.charAt( buffer.length() - 1 ) == 'e' ) { buffer.deleteCharAt( buffer.length() - 1 ); } else if ( buffer.charAt( buffer.length() - 1 ) == 's' ) { buffer.deleteCharAt( buffer.length() - 1 ); } else if ( buffer.charAt( buffer.length() - 1 ) == 'n' ) { buffer.deleteCharAt( buffer.length() - 1 ); } // "t" occurs only as suffix of verbs. else if ( buffer.charAt( buffer.length() - 1 ) == 't' ) { buffer.deleteCharAt( buffer.length() - 1 ); } else { doMore = false; } } } /** * Does some optimizations on the term. This optimisations are * contextual. */ private void optimize( StringBuffer buffer ) { // Additional step for female plurals of professions and inhabitants. if ( buffer.length() > 5 && buffer.substring( buffer.length() - 5, buffer.length() ).equals( "erin*" ) ) { buffer.deleteCharAt( buffer.length() -1 ); strip( buffer ); } // Additional step for irregular plural nouns like "Matrizen -> Matrix". if ( buffer.charAt( buffer.length() - 1 ) == ( 'z' ) ) { buffer.setCharAt( buffer.length() - 1, 'x' ); } } /** * Removes a particle denotion ("ge") from a term. */ private void removeParticleDenotion( StringBuffer buffer ) { if ( buffer.length() > 4 ) { for ( int c = 0; c < buffer.length() - 3; c++ ) { if ( buffer.substring( c, c + 4 ).equals( "gege" ) ) { buffer.delete( c, c + 2 ); return; } } } } /** * Do some substitutions for the term to reduce overstemming: * * - Substitute Umlauts with their corresponding vowel: äöü -> aou, * "ß" is substituted by "ss" * - Substitute a second char of a pair of equal characters with * an asterisk: ?? -> ?* * - Substitute some common character combinations with a token: * sch/ch/ei/ie/ig/st -> $/§/%/&/#/! */ private void substitute( StringBuffer buffer ) { substCount = 0; for ( int c = 0; c < buffer.length(); c++ ) { // Replace the second char of a pair of the equal characters with an asterisk if ( c > 0 && buffer.charAt( c ) == buffer.charAt ( c - 1 ) ) { buffer.setCharAt( c, '*' ); } // Substitute Umlauts. else if ( buffer.charAt( c ) == 'ä' ) { buffer.setCharAt( c, 'a' ); } else if ( buffer.charAt( c ) == 'ö' ) { buffer.setCharAt( c, 'o' ); } else if ( buffer.charAt( c ) == 'ü' ) { buffer.setCharAt( c, 'u' ); } // Take care that at least one character is left left side from the current one if ( c < buffer.length() - 1 ) { if ( buffer.charAt( c ) == 'ß' ) { buffer.setCharAt( c, 's' ); buffer.insert( c + 1, 's' ); substCount++; } // Masking several common character combinations with an token else if ( ( c < buffer.length() - 2 ) && buffer.charAt( c ) == 's' && buffer.charAt( c + 1 ) == 'c' && buffer.charAt( c + 2 ) == 'h' ) { buffer.setCharAt( c, '$' ); buffer.delete( c + 1, c + 3 ); substCount =+ 2; } else if ( buffer.charAt( c ) == 'c' && buffer.charAt( c + 1 ) == 'h' ) { buffer.setCharAt( c, '§' ); buffer.deleteCharAt( c + 1 ); substCount++; } else if ( buffer.charAt( c ) == 'e' && buffer.charAt( c + 1 ) == 'i' ) { buffer.setCharAt( c, '%' ); buffer.deleteCharAt( c + 1 ); substCount++; } else if ( buffer.charAt( c ) == 'i' && buffer.charAt( c + 1 ) == 'e' ) { buffer.setCharAt( c, '&' ); buffer.deleteCharAt( c + 1 ); substCount++; } else if ( buffer.charAt( c ) == 'i' && buffer.charAt( c + 1 ) == 'g' ) { buffer.setCharAt( c, '#' ); buffer.deleteCharAt( c + 1 ); substCount++; } else if ( buffer.charAt( c ) == 's' && buffer.charAt( c + 1 ) == 't' ) { buffer.setCharAt( c, '!' ); buffer.deleteCharAt( c + 1 ); substCount++; } } } } /** * Undoes the changes made by substitute(). That are character pairs and * character combinations. Umlauts will remain as their corresponding vowel, * as "ß" remains as "ss". */ private void resubstitute( StringBuffer buffer ) { for ( int c = 0; c < buffer.length(); c++ ) { if ( buffer.charAt( c ) == '*' ) { char x = buffer.charAt( c - 1 ); buffer.setCharAt( c, x ); } else if ( buffer.charAt( c ) == '$' ) { buffer.setCharAt( c, 's' ); buffer.insert( c + 1, new char[]{'c', 'h'}, 0, 2 ); } else if ( buffer.charAt( c ) == '§' ) { buffer.setCharAt( c, 'c' ); buffer.insert( c + 1, 'h' ); } else if ( buffer.charAt( c ) == '%' ) { buffer.setCharAt( c, 'e' ); buffer.insert( c + 1, 'i' ); } else if ( buffer.charAt( c ) == '&' ) { buffer.setCharAt( c, 'i' ); buffer.insert( c + 1, 'e' ); } else if ( buffer.charAt( c ) == '#' ) { buffer.setCharAt( c, 'i' ); buffer.insert( c + 1, 'g' ); } else if ( buffer.charAt( c ) == '!' ) { buffer.setCharAt( c, 's' ); buffer.insert( c + 1, 't' ); } } } } |
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