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The source code/* * Copyright 1999-2004 The Apache Software Foundation * * Licensed under the Apache License, Version 2.0 (the "License"); * you may not use this file except in compliance with the License. * You may obtain a copy of the License at * * http://www.apache.org/licenses/LICENSE-2.0 * * Unless required by applicable law or agreed to in writing, software * distributed under the License is distributed on an "AS IS" BASIS, * WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied. * See the License for the specific language governing permissions and * limitations under the License. */ package org.apache.commons.jxpath.ri.axes; import org.apache.commons.jxpath.ri.EvalContext; import org.apache.commons.jxpath.ri.compiler.NodeTest; import org.apache.commons.jxpath.ri.model.NodePointer; /** * EvalContext that walks the "parent::" axis. * * @author Dmitri Plotnikov * @version $Revision: 1.15 $ $Date: 2004/03/25 03:49:50 $ */ public class ParentContext extends EvalContext { private NodeTest nodeTest; private boolean setStarted = false; private NodePointer currentNodePointer; public ParentContext(EvalContext parentContext, NodeTest nodeTest) { super(parentContext); this.nodeTest = nodeTest; } public NodePointer getCurrentNodePointer() { return currentNodePointer; } public int getCurrentPosition() { return 1; } public int getDocumentOrder() { return -1; } public void reset() { super.reset(); setStarted = false; } public boolean setPosition(int position) { super.setPosition(position); return position == 1; } public boolean nextNode() { // Each set contains exactly one node: the parent if (setStarted) { return false; } setStarted = true; NodePointer thisLocation = parentContext.getCurrentNodePointer(); currentNodePointer = thisLocation.getImmediateParentPointer(); while (currentNodePointer != null && currentNodePointer.isContainer()) { currentNodePointer = currentNodePointer.getImmediateParentPointer(); } if (currentNodePointer != null && currentNodePointer.testNode(nodeTest)) { position++; return true; } return false; } } |
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