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Java example source code file (JJavaName.java)
The JJavaName.java Java example source code
/*
* Copyright (c) 1997, 2010, Oracle and/or its affiliates. All rights reserved.
* DO NOT ALTER OR REMOVE COPYRIGHT NOTICES OR THIS FILE HEADER.
*
* This code is free software; you can redistribute it and/or modify it
* under the terms of the GNU General Public License version 2 only, as
* published by the Free Software Foundation. Oracle designates this
* particular file as subject to the "Classpath" exception as provided
* by Oracle in the LICENSE file that accompanied this code.
*
* This code is distributed in the hope that it will be useful, but WITHOUT
* ANY WARRANTY; without even the implied warranty of MERCHANTABILITY or
* FITNESS FOR A PARTICULAR PURPOSE. See the GNU General Public License
* version 2 for more details (a copy is included in the LICENSE file that
* accompanied this code).
*
* You should have received a copy of the GNU General Public License version
* 2 along with this work; if not, write to the Free Software Foundation,
* Inc., 51 Franklin St, Fifth Floor, Boston, MA 02110-1301 USA.
*
* Please contact Oracle, 500 Oracle Parkway, Redwood Shores, CA 94065 USA
* or visit www.oracle.com if you need additional information or have any
* questions.
*/
package com.sun.codemodel.internal;
import java.util.HashSet;
import java.util.regex.Matcher;
import java.util.regex.Pattern;
/**
* Utility methods that convert arbitrary strings into Java identifiers.
*/
public class JJavaName {
/**
* Checks if a given string is usable as a Java identifier.
*/
public static boolean isJavaIdentifier(String s) {
if(s.length()==0) return false;
if( reservedKeywords.contains(s) ) return false;
if(!Character.isJavaIdentifierStart(s.charAt(0))) return false;
for (int i = 1; i < s.length(); i++)
if (!Character.isJavaIdentifierPart(s.charAt(i)))
return false;
return true;
}
/**
* Checks if the given string is a valid fully qualified name.
*/
public static boolean isFullyQualifiedClassName(String s) {
return isJavaPackageName(s);
}
/**
* Checks if the given string is a valid Java package name.
*/
public static boolean isJavaPackageName(String s) {
while(s.length()!=0) {
int idx = s.indexOf('.');
if(idx==-1) idx=s.length();
if( !isJavaIdentifier(s.substring(0,idx)) )
return false;
s = s.substring(idx);
if(s.length()!=0) s = s.substring(1); // remove '.'
}
return true;
}
/**
* <b>Experimental API: converts an English word into a plural form.
*
* @param word
* a word, such as "child", "apple". Must not be null.
* It accepts word concatanation forms
* that are common in programming languages, such as "my_child", "MyChild",
* "myChild", "MY-CHILD", "CODE003-child", etc, and mostly tries to do the right thing.
* ("my_children","MyChildren","myChildren", and "MY-CHILDREN", "CODE003-children" respectively)
* <p>
* Although this method only works for English words, it handles non-English
* words gracefully (by just returning it as-is.) For example, 日本語
* will be returned as-is without modified, not "日本語s"
* <p>
* This method doesn't handle suffixes very well. For example, passing
* "person56" will return "person56s", not "people56".
*
* @return
* always non-null.
*/
public static String getPluralForm(String word) {
// remember the casing of the word
boolean allUpper = true;
// check if the word looks like an English word.
// if we see non-ASCII characters, abort
for(int i=0; i<word.length(); i++ ) {
char ch = word.charAt(i);
if(ch >=0x80)
return word;
// note that this isn't the same as allUpper &= Character.isUpperCase(ch);
allUpper &= !Character.isLowerCase(ch);
}
for (Entry e : TABLE) {
String r = e.apply(word);
if(r!=null) {
if(allUpper) r=r.toUpperCase();
return r;
}
}
// failed
return word;
}
/** All reserved keywords of Java. */
private static HashSet<String> reservedKeywords = new HashSet
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