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Java example source code file (JJavaName.java)
The JJavaName.java Java example source code/* * Copyright (c) 1997, 2010, Oracle and/or its affiliates. All rights reserved. * DO NOT ALTER OR REMOVE COPYRIGHT NOTICES OR THIS FILE HEADER. * * This code is free software; you can redistribute it and/or modify it * under the terms of the GNU General Public License version 2 only, as * published by the Free Software Foundation. Oracle designates this * particular file as subject to the "Classpath" exception as provided * by Oracle in the LICENSE file that accompanied this code. * * This code is distributed in the hope that it will be useful, but WITHOUT * ANY WARRANTY; without even the implied warranty of MERCHANTABILITY or * FITNESS FOR A PARTICULAR PURPOSE. See the GNU General Public License * version 2 for more details (a copy is included in the LICENSE file that * accompanied this code). * * You should have received a copy of the GNU General Public License version * 2 along with this work; if not, write to the Free Software Foundation, * Inc., 51 Franklin St, Fifth Floor, Boston, MA 02110-1301 USA. * * Please contact Oracle, 500 Oracle Parkway, Redwood Shores, CA 94065 USA * or visit www.oracle.com if you need additional information or have any * questions. */ package com.sun.codemodel.internal; import java.util.HashSet; import java.util.regex.Matcher; import java.util.regex.Pattern; /** * Utility methods that convert arbitrary strings into Java identifiers. */ public class JJavaName { /** * Checks if a given string is usable as a Java identifier. */ public static boolean isJavaIdentifier(String s) { if(s.length()==0) return false; if( reservedKeywords.contains(s) ) return false; if(!Character.isJavaIdentifierStart(s.charAt(0))) return false; for (int i = 1; i < s.length(); i++) if (!Character.isJavaIdentifierPart(s.charAt(i))) return false; return true; } /** * Checks if the given string is a valid fully qualified name. */ public static boolean isFullyQualifiedClassName(String s) { return isJavaPackageName(s); } /** * Checks if the given string is a valid Java package name. */ public static boolean isJavaPackageName(String s) { while(s.length()!=0) { int idx = s.indexOf('.'); if(idx==-1) idx=s.length(); if( !isJavaIdentifier(s.substring(0,idx)) ) return false; s = s.substring(idx); if(s.length()!=0) s = s.substring(1); // remove '.' } return true; } /** * <b>Experimental API: converts an English word into a plural form. * * @param word * a word, such as "child", "apple". Must not be null. * It accepts word concatanation forms * that are common in programming languages, such as "my_child", "MyChild", * "myChild", "MY-CHILD", "CODE003-child", etc, and mostly tries to do the right thing. * ("my_children","MyChildren","myChildren", and "MY-CHILDREN", "CODE003-children" respectively) * <p> * Although this method only works for English words, it handles non-English * words gracefully (by just returning it as-is.) For example, 日本語 * will be returned as-is without modified, not "日本語s" * <p> * This method doesn't handle suffixes very well. For example, passing * "person56" will return "person56s", not "people56". * * @return * always non-null. */ public static String getPluralForm(String word) { // remember the casing of the word boolean allUpper = true; // check if the word looks like an English word. // if we see non-ASCII characters, abort for(int i=0; i<word.length(); i++ ) { char ch = word.charAt(i); if(ch >=0x80) return word; // note that this isn't the same as allUpper &= Character.isUpperCase(ch); allUpper &= !Character.isLowerCase(ch); } for (Entry e : TABLE) { String r = e.apply(word); if(r!=null) { if(allUpper) r=r.toUpperCase(); return r; } } // failed return word; } /** All reserved keywords of Java. */ private static HashSet<String> reservedKeywords = new HashSet Other Java examples (source code examples)Here is a short list of links related to this Java JJavaName.java source code file: |
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