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Java example source code file (Regex.java)

This example Java source code file (Regex.java) is included in the alvinalexander.com "Java Source Code Warehouse" project. The intent of this project is to help you "Learn Java by Example" TM.

Learn more about this Java project at its project page.

Java - Java tags/keywords

exception, regex, string, test

The Regex.java Java example source code

/*
 * Copyright (c) 2001, 2003, Oracle and/or its affiliates. All rights reserved.
 * DO NOT ALTER OR REMOVE COPYRIGHT NOTICES OR THIS FILE HEADER.
 *
 * This code is free software; you can redistribute it and/or modify it
 * under the terms of the GNU General Public License version 2 only, as
 * published by the Free Software Foundation.
 *
 * This code is distributed in the hope that it will be useful, but WITHOUT
 * ANY WARRANTY; without even the implied warranty of MERCHANTABILITY or
 * FITNESS FOR A PARTICULAR PURPOSE.  See the GNU General Public License
 * version 2 for more details (a copy is included in the LICENSE file that
 * accompanied this code).
 *
 * You should have received a copy of the GNU General Public License version
 * 2 along with this work; if not, write to the Free Software Foundation,
 * Inc., 51 Franklin St, Fifth Floor, Boston, MA 02110-1301 USA.
 *
 * Please contact Oracle, 500 Oracle Parkway, Redwood Shores, CA 94065 USA
 * or visit www.oracle.com if you need additional information or have any
 * questions.
 */

/* @test
 * @bug 4808962
 * @summary Unit tests for String regex methods
 */


public class Regex {

    static void ck(boolean x, boolean ans) throws Exception {
        if (x != ans)
            throw new Exception("Test failed");
    }

    static void ck(String x, String ans) throws Exception {
        if (!x.equals(ans))
            throw new Exception("Test failed");
    }

    static void ck(String[] x, String[] ans) throws Exception {
        if (x.length != ans.length)
            throw new Exception("Test failed");
        for (int i = 0; i < x.length; i++) {
            if (!x[i].equals(ans[i]))
                throw new Exception("Test failed");
        }
    }

    static void testLiteralReplacement() throws Exception {
        // Test straightforward replacement
        String data = "abcdefghi";
        String result = data.replace("def", "abc");
        if (!result.equals("abcabcghi"))
            throw new Exception("Test failed");

        // Test replacement with target that has metacharacters
        data = "abc(def)?ghi";
        result = data.replace("(def)?", "abc");
        if (!result.equals("abcabcghi"))
            throw new Exception("Test failed");

        // Test replacement with replacement that has metacharacters
        data = "abcdefghi";
        result = data.replace("def", "\\ab$c");
        if (!result.equals("abc\\ab$cghi"))
            throw new Exception("Test failed");
    }

    public static void main(String[] args) throws Exception {

        // These don't need to be thorough, they just need to check
        // that we're properly hooked up to java.util.regex

        String foo = "boo:and:foo";

        ck(foo.matches("b+"), false);
        ck(foo.matches("o+"), false);
        ck(foo.matches("b..:and:f.*"), true);

        ck(foo.replaceAll("oo", "uu"), "buu:and:fuu");
        ck(foo.replaceAll("o+", "<$0>"), "b:and:f");

        ck(foo.replaceFirst("oo", "uu"), "buu:and:foo");
        ck(foo.replaceFirst("o+", "<$0>"), "b:and:foo");

        ck(foo.split(":"), new String[] { "boo", "and", "foo" });
        ck(foo.split("o"), new String[] { "b", "", ":and:f" });

        ck(foo.split(":", 2), new String[] { "boo", "and:foo" });
        ck(foo.split("o", -2), new String[] { "b", "", ":and:f", "", "" });

        testLiteralReplacement();
    }


}

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