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Java example source code file (CacheTest.java)
The CacheTest.java Java example source code/* * Copyright (c) 2002, 2011, Oracle and/or its affiliates. All rights reserved. * DO NOT ALTER OR REMOVE COPYRIGHT NOTICES OR THIS FILE HEADER. * * This code is free software; you can redistribute it and/or modify it * under the terms of the GNU General Public License version 2 only, as * published by the Free Software Foundation. * * This code is distributed in the hope that it will be useful, but WITHOUT * ANY WARRANTY; without even the implied warranty of MERCHANTABILITY or * FITNESS FOR A PARTICULAR PURPOSE. See the GNU General Public License * version 2 for more details (a copy is included in the LICENSE file that * accompanied this code). * * You should have received a copy of the GNU General Public License version * 2 along with this work; if not, write to the Free Software Foundation, * Inc., 51 Franklin St, Fifth Floor, Boston, MA 02110-1301 USA. * * Please contact Oracle, 500 Oracle Parkway, Redwood Shores, CA 94065 USA * or visit www.oracle.com if you need additional information or have any * questions. */ /* @test * @bug 4292867 * @summary Check that InetAddress doesn't continue to throw UHE * after the name service has recovered and the negative ttl * on the initial lookup has expired. * @compile -XDignore.symbol.file=true SimpleNameService.java * SimpleNameServiceDescriptor.java * @run main/othervm/timeout=200 -Dsun.net.spi.nameservice.provider.1=simple,sun CacheTest */ import java.net.InetAddress; import java.net.UnknownHostException; import java.security.Security; public class CacheTest { public static void main(String args[]) throws Exception { /* * First check the ttl on negative lookups is in the <15 second * range. If the ttl is <=0 it means we cache forever or always * consult the name service. For ttl > 15 the test would take * too long so we skip it (need to coordinate jtreg timeout * with negative ttl) */ String ttlProp = "networkaddress.cache.negative.ttl"; int ttl = 0; String policy = Security.getProperty(ttlProp); if (policy != null) { ttl = Integer.parseInt(policy); } if (ttl <= 0 || ttl > 15) { System.err.println("Security property " + ttlProp + " needs to " + " in 1-15 second range to execute this test"); return; } /* * The following outlines how the test works :- * * 1. Do a lookup via InetAddress.getByName that it guaranteed * to succeed. This forces at least one entry into the cache * that will not expire. * * 2. Do a lookup via InetAddress.getByName that is guarnateed * to fail. This results in a negative lookup cached for * for a short period to time. * * 3. Wait for the cache entry to expire. * * 4. Do a lookup (which should consult the name service) and * the lookup should succeed. */ // name service needs to resolve this. SimpleNameService.put("theclub", "129.156.220.219"); // this lookup will succeed InetAddress.getByName("theclub"); // lookup "luster" - this should throw UHE as name service // doesn't know anything about this host. try { InetAddress.getByName("luster"); throw new RuntimeException("Test internal error " + " - luster is bring resolved by name service"); } catch (UnknownHostException x) { } // name service now needs to know about luster SimpleNameService.put("luster", "10.5.18.21"); // wait for the cache entry to expire and lookup should // succeed. Thread.currentThread().sleep(ttl*1000 + 1000); InetAddress.getByName("luster"); } } Other Java examples (source code examples)Here is a short list of links related to this Java CacheTest.java source code file: |
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