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Java example source code file (FindASCIICodingBugs.java)
The FindASCIICodingBugs.java Java example source code/* * Copyright (c) 2008, Oracle and/or its affiliates. All rights reserved. * DO NOT ALTER OR REMOVE COPYRIGHT NOTICES OR THIS FILE HEADER. * * This code is free software; you can redistribute it and/or modify it * under the terms of the GNU General Public License version 2 only, as * published by the Free Software Foundation. * * This code is distributed in the hope that it will be useful, but WITHOUT * ANY WARRANTY; without even the implied warranty of MERCHANTABILITY or * FITNESS FOR A PARTICULAR PURPOSE. See the GNU General Public License * version 2 for more details (a copy is included in the LICENSE file that * accompanied this code). * * You should have received a copy of the GNU General Public License version * 2 along with this work; if not, write to the Free Software Foundation, * Inc., 51 Franklin St, Fifth Floor, Boston, MA 02110-1301 USA. * * Please contact Oracle, 500 Oracle Parkway, Redwood Shores, CA 94065 USA * or visit www.oracle.com if you need additional information or have any * questions. */ /* @test * @bug 6196991 * @summary Roundtrip Encoding/Decoding of just one ASCII char * @author Martin Buchholz */ import java.util.*; import java.nio.*; import java.nio.charset.*; public class FindASCIICodingBugs { private static int failures = 0; private static void check(boolean condition) { if (! condition) { new Error("test failed").printStackTrace(); failures++; } } private static boolean equals(byte[] ba, ByteBuffer bb) { if (ba.length != bb.limit()) return false; for (int i = 0; i < ba.length; i++) if (ba[i] != bb.get(i)) return false; return true; } public static void main(String[] args) throws Exception { for (Map.Entry<String,Charset> e : Charset.availableCharsets().entrySet()) { String csn = e.getKey(); Charset cs = e.getValue(); // Delete the following lines when these charsets are fixed! if (csn.equals("x-JIS0208")) continue; // MalformedInput if (csn.equals("JIS_X0212-1990")) continue; // MalformedInput if (! cs.canEncode()) continue; CharsetEncoder enc = cs.newEncoder(); CharsetDecoder dec = cs.newDecoder(); if (! enc.canEncode('A')) continue; System.out.println(csn); try { byte[] bytes1 = "A".getBytes(csn); ByteBuffer bb = enc.encode(CharBuffer.wrap(new char[]{'A'})); check(equals(bytes1, bb)); check(new String(bytes1, csn).equals("A")); CharBuffer cb = dec.decode(bb); check(cb.toString().equals("A")); } catch (Throwable t) { t.printStackTrace(); failures++; } } if (failures > 0) throw new Exception(failures + "tests failed"); } } Other Java examples (source code examples)Here is a short list of links related to this Java FindASCIICodingBugs.java source code file: |
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