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Scala example source code file (Any.scala)
The Scala Any.scala source code/* __ *\ ** ________ ___ / / ___ Scala API ** ** / __/ __// _ | / / / _ | (c) 2002-2010, LAMP/EPFL ** ** __\ \/ /__/ __ |/ /__/ __ | http://scala-lang.org/ ** ** /____/\___/_/ |_/____/_/ | | ** ** |/ ** \* */ package scala /** Class `Any` is the root of the Scala class hierarchy. Every class in a Scala * execution environment inherits directly or indirectly from this class. */ abstract class Any { /** Compares the receiver object (`this`) with the argument object (`that`) for equivalence. * * The default implementations of this method is an [[http://en.wikipedia.org/wiki/Equivalence_relation equivalence relation]]: * * - It is reflexive: for any instance `x` of type `Any`, `x.equals(x)` should return `true`. * - It is symmetric: for any instances `x` and `y` of type `Any`, `x.equals(y)` should return `true` if and * only if `y.equals(x)` returns `true`. * - It is transitive: for any instances `x`, `y`, and `z` of type `AnyRef` if `x.equals(y)` returns `true` and * `y.equals(z)` returns `true`, then `x.equals(z)` should return `true`. * * If you override this method, you should verify that your implementation remains an equivalence relation. * Additionally, when overriding this method it is usually necessary to override `hashCode` to ensure that * objects which are "equal" (`o1.equals(o2)` returns `true`) hash to the same [[scala.Int]]. * (`o1.hashCode.equals(o2.hashCode)`). * * @param that the object to compare against this object for equality. * @return `true` if the receiver object is equivalent to the argument; `false` otherwise. */ def equals(that: Any): Boolean /** Calculate a hash code value for the object. * * The default hashing algorithm is platform dependent. * * Note that it is allowed for two objects to have identical hash codes (`o1.hashCode.equals(o2.hashCode)`) yet * not be equal (`o1.equals(o2)` returns `false`). A degenerate implementation could always return `0`. * However, it is required that if two objects are equal (`o1.equals(o2)` returns `true`) that they have * identical hash codes (`o1.hashCode.equals(o2.hashCode)`). Therefore, when overriding this method, be sure * to verify that the behavior is consistent with the `equals` method. * * @return the hash code value for this object. */ def hashCode: Int /** Returns a string representation of the object. * * The default representation is platform dependent. * * @return a string representation of the object. */ def toString: String /** Returns the runtime class representation of the object. * * @return a class object corresponding to the static type of the receiver */ def getClass(): Class[_] /** Test two objects for equality. * * @param that the object to compare against this object for equality. * @return `true` if the receiver object is equivalent to the argument; `false` otherwise. */ final def ==(that: Any): Boolean = this equals that /** Test two objects for inequality. * * @param that the object to compare against this object for equality. * @return `true` if !(this == that), false otherwise. */ final def != (that: Any): Boolean = !(this == that) /** Equivalent to `x.hashCode` except for boxed numeric types. * For numerics, it returns a hash value which is consistent * with value equality: if two value type instances compare * as true, then ## will produce the same hash value for each * of them. * * @return a hash value consistent with == */ final def ## : Int = sys.error("##") /** Test whether the dynamic type of the receiver object is `T0`. * * Note that the result of the test is modulo Scala's erasure semantics. * Therefore the expression `1.isInstanceOf[String]` will return `false`, while the * expression `List(1).isInstanceOf[List[String]]` will return `true`. * In the latter example, because the type argument is erased as part of compilation it is * not possible to check whether the contents of the list are of the specified type. * * @return `true` if the receiver object is an instance of erasure of type `T0`; `false` otherwise. */ def isInstanceOf[T0]: Boolean = sys.error("isInstanceOf") /** Cast the receiver object to be of type `T0`. * * Note that the success of a cast at runtime is modulo Scala's erasure semantics. * Therefore the expression `1.asInstanceOf[String]` will throw a `ClassCastException` at * runtime, while the expression `List(1).asInstanceOf[List[String]]` will not. * In the latter example, because the type argument is erased as part of compilation it is * not possible to check whether the contents of the list are of the requested type. * * @throws ClassCastException if the receiver object is not an instance of the erasure of type `T0`. * @return the receiver object. */ def asInstanceOf[T0]: T0 = sys.error("asInstanceOf") } Other Scala examples (source code examples)Here is a short list of links related to this Scala Any.scala source code file: |
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