Spring Framework example source code file (PatternMatchUtils.java)

This example Spring Framework source code file (PatternMatchUtils.java) is included in the DevDaily.com "Java Source Code Warehouse" project. The intent of this project is to help you "Learn Java by Example" ^TM.

Java - Spring Framework tags/keywords

patternmatchutils, patternmatchutils, string, string

The Spring Framework PatternMatchUtils.java source code

/*
 * Copyright 2002-2007 the original author or authors.
 *
 * Licensed under the Apache License, Version 2.0 (the "License");
 * you may not use this file except in compliance with the License.
 * You may obtain a copy of the License at
 *
 *      http://www.apache.org/licenses/LICENSE-2.0
 *
 * Unless required by applicable law or agreed to in writing, software
 * distributed under the License is distributed on an "AS IS" BASIS,
 * WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied.
 * See the License for the specific language governing permissions and
 * limitations under the License.
 */

package org.springframework.util;

/**
 * Utility methods for simple pattern matching, in particular for
 * Spring's typical "xxx*", "*xxx" and "*xxx*" pattern styles.
 *
 * @author Juergen Hoeller
 * @since 2.0
 */
public abstract class PatternMatchUtils {

	/**
	 * Match a String against the given pattern, supporting the following simple
	 * pattern styles: "xxx*", "*xxx", "*xxx*" and "xxx*yyy" matches (with an
	 * arbitrary number of pattern parts), as well as direct equality.
	 * @param pattern the pattern to match against
	 * @param str the String to match
	 * @return whether the String matches the given pattern
	 */
	public static boolean simpleMatch(String pattern, String str) {
		if (pattern == null || str == null) {
			return false;
		}
		int firstIndex = pattern.indexOf('*');
		if (firstIndex == -1) {
			return pattern.equals(str);
		}
		if (firstIndex == 0) {
			if (pattern.length() == 1) {
				return true;
			}
			int nextIndex = pattern.indexOf('*', firstIndex + 1);
			if (nextIndex == -1) {
				return str.endsWith(pattern.substring(1));
			}
			String part = pattern.substring(1, nextIndex);
			int partIndex = str.indexOf(part);
			while (partIndex != -1) {
				if (simpleMatch(pattern.substring(nextIndex), str.substring(partIndex + part.length()))) {
					return true;
				}
				partIndex = str.indexOf(part, partIndex + 1);
			}
			return false;
		}
		return (str.length() >= firstIndex &&
				pattern.substring(0, firstIndex).equals(str.substring(0, firstIndex)) &&
				simpleMatch(pattern.substring(firstIndex), str.substring(firstIndex)));
	}

	/**
	 * Match a String against the given patterns, supporting the following simple
	 * pattern styles: "xxx*", "*xxx", "*xxx*" and "xxx*yyy" matches (with an
	 * arbitrary number of pattern parts), as well as direct equality.
	 * @param patterns the patterns to match against
	 * @param str the String to match
	 * @return whether the String matches any of the given patterns
	 */
	public static boolean simpleMatch(String[] patterns, String str) {
		if (patterns != null) {
			for (int i = 0; i < patterns.length; i++) {
				if (simpleMatch(patterns[i], str)) {
					return true;
				}
			}
		}
		return false;
	}

}